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標題:
請問android studio的猜數字AB的升級版要怎麼寫
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作者:
fto123
時間:
2024-4-5 11:37 PM
標題:
請問android studio的猜數字AB的升級版要怎麼寫
各位學長 大家好
小弟這學期修了
android studio
老師出作業要寫猜數字
雖然參考網路上的分享與同學的幫忙寫完AB邏輯
但是老師又出了一個升級版，要加算C
作業預設4個數字
新邏輯是要先計算生成的隨機數是否有重複值
若有重複值，就要拿手動輸入的值來比對
若手動輸入值與重複值相等，則C+1，若無，則C=0
且每一個手動輸入值都要算
但是想不出邏輯要怎麼解，請各位學長幫忙
謝謝
MainActivity.java如下
package
com.example.ch5_2;
import
androidx.appcompat.app.AppCompatActivity;
import
android.os.Bundle;
import
android.view.Menu;
import
android.view.MenuInflater;
import
android.view.View;
import
android.widget.Button;
import
android.widget.EditText;
import
android.widget.TextView;
import
android.view.View.OnClickListener;
public class
MainActivity
extends
AppCompatActivity
{
private int
systemA
,
systemB
,
systemC
,
systemD
;
private
String
strA
,
strB
,
strC
,
strD
,
resault
;
Button
submit
;
@Override
public boolean
onCreateOptionsMenu
(Menu menu) {
MenuInflater inflater = getMenuInflater();
inflater.inflate(R.menu.
menu_main
, menu);
return super
.onCreateOptionsMenu(menu);
}
@Override
protected void
onCreate
(Bundle savedInstanceState) {
super
.onCreate(savedInstanceState);
setContentView(R.layout.
activity_main
);
getNum();
submit
= (Button)
this
.findViewById(R.id.
button
);
submit
.setOnClickListener(
new
OnClickListener() {
public void
onClick
(View arg0) {
EditText text = (EditText) findViewById(R.id.
txtTemp
);
TextView tv = (TextView) findViewById(R.id.
lblOutput
);
TextView output2 = (TextView) findViewById(R.id.
lblOutput2
);
String myA, myB, myC, myD;
int
a =
0
;
int
b =
0
;
// int C = 0;
myA = text.getText().toString().substring(
0
,
1
);
myB = text.getText().toString().substring(
1
,
2
);
myC = text.getText().toString().substring(
2
,
3
);
myD = text.getText().toString().substring(
3
,
4
);
// if (myA.equals(myB) || myB.equals(myC) || myC.equals(myA)) {
// resault="
輸入錯誤
,
請輸入三個不重複的數字
";
// tv.setText(resault);
// text.setText("");
// } else {
if
(myA.equals(
strA
) && myB.equals(
strB
) && myC.equals(
strC
) && myD.equals(
strD
))
{
tv.setText(
"Input
的數字
:"
+ myA + myB + myC + myD +
"
恭喜你答對囉
~
答案
: "
+
strA
+
strB
+
strC
+
strD
);
}
else
{
if
(myA.equals(
strA
)) {
a +=
1
;
}
else if
(myA.equals(
strB
)) {
b +=
1
;
}
else if
(myA.equals(
strC
)) {
b +=
1
;
}
else if
(myA.equals(
strD
)) {
b +=
1
;
}
if
(myB.equals(
strB
)) {
a +=
1
;
}
else if
(myB.equals(
strA
)) {
b +=
1
;
}
else if
(myB.equals(
strC
)) {
b +=
1
;
}
else if
(myB.equals(
strD
)) {
b +=
1
;
}
if
(myC.equals(
strC
)) {
a +=
1
;
}
else if
(myC.equals(
strA
)) {
b +=
1
;
}
else if
(myC.equals(
strB
)) {
b +=
1
;
}
else if
(myC.equals(
strD
)) {
b +=
1
;
}
if
(myD.equals(
strD
)) {
a +=
1
;
}
else if
(myD.equals(
strA
)) {
b +=
1
;
}
else if
(myD.equals(
strB
)) {
b +=
1
;
}
else if
(myD.equals(
strC
)) {
b +=
1
;
}
resault
=
"Input
的數字
:"
+ myA + myB + myC + myD +
"="
+ a +
"A"
+ b +
"B"
;
// + c "C";
tv.setText(
resault
);
output2.setText((tv.getText() +
"
\n
"
) + output2.getText());
text.setText(
""
);
//
清空輸入框
}
}
});
}
public void
getNum
() {
systemA
= (
int
) (Math.
random
() *
10
);
systemB
= (
int
) (Math.
random
() *
10
);
systemC
= (
int
) (Math.
random
() *
10
);
systemD
= (
int
) (Math.
random
() *
10
);
// if (systemB == systemA) {
// systemB = (int) (Math.random() * 10);
// }
// if (systemC == systemB || systemC == systemA) {
// systemC = (int) (Math.random() * 10);
// }
strA
= String.
valueOf
(
systemA
);
strB
= String.
valueOf
(
systemB
);
strC
= String.
valueOf
(
systemC
);
strD
= String.
valueOf
(
systemD
);
}
}
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